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I need to find two solutions to this differential equation.
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dy/dx=1-2y
this is a separable differential equation...have u tried it yet?
I can only find one, I just found y = (1-Ae^(-2x))/2 where A = e^2c
SOmehow the solutions say the other solution is (Ae^(-2x) + 1 )/2
But I cannot see how they got that
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are you given multiple initial conditions?
I am given no initial conditions
oh but you already have a constant... nvmd
\[dy/(1-2y)=dx\] \[\sqrt{1-2y}=Ce ^{x}\] \[1-2y = \pm Ce ^{x}\]
I mean remember absolute value with\[\int\frac{du}u=\ln|u|+C\] :P
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Oh Yeah I get you
Thanks
welcome!
that comes out nicely from the square root anyway
Thanks Myko
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yw
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