Question

A space probe is traveling in outer space with a momentum that has a magnitude of 3.87 x 107 kg·m/s. A retrorocket is fired to slow down the probe. It applies a force to the probe that has a magnitude of 1.41 x 106 N and a direction opposite to the probe's motion. It fires for a period of 9.55 s. Determine the momentum of the probe after the retrorocket ceases to fire.

Answer 1

i think it is 2.52345 x 10^7 kg m/sec but im not sure so im asking all of you if im right!

Answer 2

yp thats right lol

Answer 3

lol ok do the math for me lol

Answer 4

absolutely ur answer is correct

Answer 5

1 Newton is 1 kg-m/s^2

You have a force of 1.41 * 10^6 N, and it was applied for 9.55 second.

Can't you see that multiplying the force by the duration gives a value that will be expressed in "kg-m/s"?

If you multiple Kg m/sec ^ 2 by a value in seconds, you get Kg m/sec

When you are writing exponential numbers, use the ^ (up arrow) sign to show that it is a power, so that 3.87 x 10^7.

The final answer should be 2.52345 x 10^7 kg m/sec

Answer 6

yep i was gonna say the same thing

Answer 7

sorry to say it first

Answer 8

well hope u got that @yoloxlarge

Answer 9

its ok

Answer 10

awsme thanks lol

Answer 11

my pleasure