The figure below shows AB = 2 units and BD = 5 units. If the area of triangle ADE is 70 square units, what is the area of the trapezoid BCED? 58.80 square units 5.71 square units 7.53 square units 64.29 square units
7.53??
im wondering if the cow is going a ratio solution
9i have no clue
no its not 7.53 you have to solve this using proportions...and that ratio of areas = ratio of sides squared for triangle ADE, length of side is 7 and Area is 70 for smaller triangle ABC, length of side is 2, Area is A \[\frac{A}{70} = (\frac{2}{7})^{2}\] then the trapezoid is the difference in the areas
i knew it had to be something along those lines ;)
im so lost
yep :) is there a better way?
if we take a general stab it this, and determine the relationship that exists between similar triangles and their areas i get this \[A_{t1}=\frac{bh}{2}\] \[A_{t2}=\frac{n^2bh}{2}\]
i just read that if you cant solve a problem in more than one way; than you cant solve the problem ;)
@TiaW the 2 triangles are similar, thats why i can use the proportion first solve for Area of smaller triangle, solve for A in the equation i posted
since we know more of the larger triangle; lets use that as firsties 7:2 such that 1: 2/7 is the proportion of sides lengths so the area im thinking would be (2/7)^2 to be proportional
would that be 70?
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the area? no the area of triangle ADE is 70 area of triangle ABC is much smaller
i dont know how to solve that
@amistre64 good job....but thats exactly what i did
what is (2/7)^2 ?
4/49
good, so now you have \[\frac{A}{70} = \frac{4}{49}\] how do you move the 70 to other side, so is A is by itself?
280a=28 a=10
but 10/70 does not equal 4/49 how did you get 280a = 28 ?
... in my defense, what i did may seem exactly like what you did, but i did it with one brain cell tied behind my cerebral cortex ;)
opps. 49A=280 a=5.71
haha...it was a better explanation , i will give you that :)
very good :) now subtract that from 70 to get area of trapezoid
70-5.71=64.29?
yep
thank u bunches
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