Question

Which ratio represents the area of the smaller rectangle compared to the area of the larger rectangle? (Figure not drawn to scale)

Answer 1

The area of a rectangle is A=LW. Therefore, the ratio of the two rectangles would be:\[\Large \frac{LW_{smallrect}}{LW_{largerect}}=\frac{(x)(x+3)}{(x^2+7x+12)(3x)}\]You can obviously simplify that...

Answer 2

x(x+3) x+3
---------------- = -------------------
3x(x^2 +7x +12) 3(x+3)(x+4)

Answer 3

area of smaller rectangle is x multiplied by x+3
area of larger triangle ex multiplied by x^2+7x+12

X^2+7x+12 can be factorized as X+4 (X+3)

take ratio of the first to second

Answer 4

x+3 over x^2 +7x +12 right

Answer 5

\[\frac{(x)(x+3)}{(x^2+7x+12)(3x)}\]\[=\frac{(x)(x+3)}{(x+3)(x+4)(3x)}\]\[=\frac{x}{(x+4)(3x)}\]\[=\frac{x}{3x^2+12x}\]\[=\frac{1}{3x+12}\]

Answer 6

im i right

Answer 7

You're right if you ended up with \[\frac{1}{3x+12}\]

Answer 8

thats not in the choices

Answer 9

What are the choices then? The above is the simplified version.

Answer 10

Ok...only one of those is equivalent to \[\frac{1}{3x+12}\]Which do you think it is?

Answer 11

\[1/3(x+4)\]

Answer 12

Bingo :)

Answer 13

ok thanks

Answer 14

yw