Prove that the opposite angles of a parallelogram are congruent.
@satellite73 @amistre64 @jim_thompson5910
If we wanted to prove <1 = <3, then you would have to prove that triangles BAD and DCB are congruent
whats the proof then?
To do this, you use the idea that BD = BD (reflexive property), BC = AD (opposite sides of parallelogram are equal), and BA = CD (opposite sides of parallelogram are equal)
then you use the SSS property of congruence
So the basic proof outline is: BD = BD (reflexive property) BC = AD (opposite sides of parallelogram are equal) BA = CD (opposite sides of parallelogram are equal) These three facts lead to the fact that triangles BAD and DCB are congruent By the CPCTC property, angle 1 and angle 3 are congruent
Note: CPCTC stands for "corresponding parts of congruent triangles are congruent"
Then use this idea to show that angles 2 and 4 are congruent
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