Question

For a holiday party, Kathleen is making a six-layer torte, which consists of six 6-inch diameter cake layers with a cream topping on each layer. She knows that one recipe of cream will cover 45 square inches of cake. How many batches of the topping must she make to complete her torte? ( A = p )(Use p = 3.14 as an approximate value)
4 batches
3 batches
16 batches
15 batches

Answer 1

Do you know how to get the area of a circle?

Answer 2

I was never good at math. -.-

Answer 3

No problem. The area of a circle is:\[A_{circle}=\pi * radius^2\]That's the same as \[A_{circle}=\pi (\frac{diameter}{2})^2\]So each cake layer will have an area of \[A=\pi 3^2=28.27in^2\]And the cake has 6 layers so the total area becomes:\[(6)(28.27in^2)=169.62in^2\]How many batches would it take to fill that amount of area if each batch is 45 in^2?

Answer 4

3.75^2 right? Which is basically 4?

Answer 5

You got it :)

Answer 6

can you help me with another real fast?
[(1/2)^3 - (1/4)2]2^3

Answer 7

Ok. To be clear, is that this?\[[(\frac{1}{2})^3-\frac{1}{4}2)]2^3\]

Answer 8

Yeah

Answer 9

Ack Im sorry... the 2 after the 1/4 is an exponent

Answer 10

Just re-looked at the homework problem

Answer 11

I kinda thought it would be :) Ok, take it in pieces. Starting inside the brackets...
\[(\frac{1}{2})^3=\frac{1^3}{2^3}=\frac{1}{8}\]and\[(\frac{1}{4})^2=\frac{1^2}{4^2}=\frac{1}{16}\]And you should know that 2^3 = 8.

So now we have this:\[8(\frac{1}{8}-\frac{1}{16})=?\]All you need to do is distribute the 8 and perform the subtraction.

Answer 12

1/2

Answer 13

Yep

Answer 14

THank you much

Answer 15

yw