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Mathematics 22 Online
OpenStudy (anonymous):

[6.05]A concert hall earned $40,000 in sold−out comedy ticket sales. Front section tickets cost $150 per seat and back section tickets cost $50 per seat. The number of front section seats is three times the number of back section seats. How many seats are in the front section?

OpenStudy (shane_b):

Let the front seats be x and the back seats be y: 150x+50y=40000 3y = x Can you solve it from here?

OpenStudy (anonymous):

no i need a little more help

OpenStudy (shane_b):

Sorry...phone. Give me a few

OpenStudy (anonymous):

ok thanks lol

OpenStudy (anonymous):

my laptops about to die lol...hurry!!!!

OpenStudy (anonymous):

lol

OpenStudy (shane_b):

Ok. We'll use the substitution method since that's the easiest in this case. Since x=3y plug 3y back into the first equation and solve for y. Once you know what y is, you can easily figure out x. \[150(3y)+50y=40000\]\[y=80\]Using the second equation and plugging in 80 you get:\[3(80)=x=240\]If you plug all that back into the original question you'll see that it works out :)

OpenStudy (anonymous):

so x equals 240?

OpenStudy (shane_b):

Yes...there are 240 front seats and 80 back seats

OpenStudy (anonymous):

thanks bro

OpenStudy (shane_b):

np

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