Question

The perimeter of a rectangle is 40 ft. The length is 6 feet longer than the width. Find the dimensions. Write a system of linear equations and solve the resulting system. Let x be the length and y be the width. Write the first equation 2x+2y= Write the second equation x=y+ What is the length? What is the width?

Answer 1

some one help me???? Please!!!

Answer 2

Let l = length
Let w = width
we will now write the equation for the perimeter 40=2l +2w Do you follow that for that equation?

Answer 3

yes

Answer 4

Now for the 2nd equation: We were told that l=w + 6

Answer 5

right

Answer 6

Let us put the two equations down one below the other and simplified;
2l + 2w = 40
l - w = 6
Do you want to solve using substitution or the "elimination" method?

Answer 7

elimination

Answer 8

so it would be l=w=34?

Answer 9

l-w=34

Answer 10

After reading the instructions in your problem, I should of used x and y but I believe you still understant. The length is 6 ft longer than the width so it is l-w=6

Answer 11

ok

Answer 12

Multiply that equation by 2 2(l-w=6) you will now get 2l - 2w = 12 we now rack em and stack em.

2l + 2w = 40
2l -2w =12
--------------- Lets add
4l =52
l=13 ft Then width will be 6 ft shorter or 7 ft. Check Check
13 + 13 + 7 + 7= 40 Check good
7+6 = 13 check good Bingo good answer.

Answer 13

That was the elimination method.

Answer 14

If you let l be x and w be y you will have complied with the instructions in your problem.

Answer 15

ok thank you.