Write the equation of the line that is perpendicular to the line 2x − 3y = 3 and passes through the point (−8, 2). look at picture **
we need the slope of the given equation. to identify it, rewrite the equation given in y=mx+b form. where m =slope. then, since the equation we are finding is perpendicular to the given slope, slope of our line = negative reciprocal of the slope of the equation given. Then, when we have the slope already, use the y-y1=(m)(x-x1). plug-in m =slope and x1 = abscissa of the given point, and y1=ordinate.
I don't get... so what would the final equation be to solve for? @violy
try to write the given equation in the form y=mx +b first.
by the way, we can use other method to solve for m. since its in the form ax +by = c. m =slope= -a/b.
example: 3x - 5y= 7. slope = -a/b = -((3)/(-5))=-(-3/5)=3/5. make sense?
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