An investor invested a total of $1900 in two mutual funds. One fund earned a 8 percent profit while the other earned a 3 percent profit. If the invester's total profit was $72 how much was invested in each mutual fund?

Question

anonymous · Answer

$$.09x+.03(1900-x)=72$$ is what you need so solve

anonymous · Answer

probably easiest to multiply by $100$ and solve 
$$9x+3(1900-x)=7200$$

anonymous · Answer

ok ty

anonymous · Answer

reasoning that if you put $x$ as the amount invested at 9% it makes $.09x$ dollars, while the rest of the money  $1900-x$ invested at 3% makes $.03(1900-x)$  for a total of $$.09x+.03(1900-x)$$

anonymous · Answer

yw

anonymous · Answer

it was at 8 percent not 9 percent so im confused