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If the equation x^2-kx+3k=0 has exactly 1 solution for "x", which of the following could be "k"? 4 6 9 12 18
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b^2-4ac has to be 0
what?
use the discriminant?
solve it. you need one solution, so you need discriminant to be 0
hmmmm..... but this equation is structured a little differently
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b^2-4ac=0 so (-k)^2-4*1*3k=0 k^2-12k=0
k(k-12)=0 k=0 or k=12
so k=12
thank u. i'll need 2 remember this for future reference. thanx, bro
generally... remember that
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thanx, anyway, bro
|dw:1345411603269:dw| no matter k's and stuff
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