Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

A ball of diameter 20 cm fits exactly inside a cylindrical container, as shown below The maximum volume of liquid which can be poured into the cylindrical container when empty is ________ cm3. [π=3.14]

OpenStudy (anonymous):

OpenStudy (anonymous):

hint: The diameter and length of the cylinder is the same

hartnn (hartnn):

and these both ^^ are equal to diameter of ball

OpenStudy (anonymous):

that's too much of a hint already

OpenStudy (anonymous):

so im looking for the volume V=pi.*5^2 *10 is tht right? and you get 758.4

OpenStudy (anonymous):

first, write down the volume formula of a cylinder

OpenStudy (anonymous):

V = 22/7r^2h

OpenStudy (anonymous):

785.7 i thnk is the answer

OpenStudy (anonymous):

\[v=\pi r^{2}h\]

OpenStudy (anonymous):

thts wat i put . i use 22/7 as Pi

OpenStudy (anonymous):

plug the values in

OpenStudy (anonymous):

v = 22/7 * 5^2 * 10 v = 22/7 * 25 * 10 V=3.142857142837143 * 25 * 10 v = 78.5 rounded is 78.6 * 10 v= 786

OpenStudy (anonymous):

does it look like this? \[v=(3.14)(10)^{2}(20)\]

OpenStudy (anonymous):

where did you get the 25?

OpenStudy (anonymous):

nooooo bc i put 5 but ts wrong bc yu say 10 so let me redo it

OpenStudy (anonymous):

\[r=\frac{ d }{ 2 }\]

OpenStudy (anonymous):

i got 6280

OpenStudy (anonymous):

is that answer one of the choices or something quite near the value?

OpenStudy (anonymous):

well it isnt multiple choice

OpenStudy (anonymous):

k. assuming that the pi value is 3.14 then you're right on the ball

OpenStudy (anonymous):

http://www.mathopenref.com/radius.html

OpenStudy (anonymous):

thank you so very much . i have 2 more questions. to go then im done .

OpenStudy (anonymous):

look at that link to see what other information you can learn about radius and diameter

OpenStudy (anonymous):

thank you

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!