Question

indefinite integral problem? (see attached)
I have work

Answer 1

try taking the whole denominator as u

Answer 2

@ghass1978 I'm not getting anywhere

Answer 3

\[u=1+\sqrt{2x}\implies du=\frac{dx}{\sqrt{2x}}=\frac{dx}{u-1}\implies dx=(u-1)du\]

Answer 4

Let's see if I can take it from there

Answer 5

I should mention that you should never try to syb \[u=\sqrt x\]without the 2 under the radical like you did
if there is a 2 in the radical it must be in the u-sub somewhere

Answer 6

sub*

Answer 7

Is this right?

Answer 8

yes, but don't forget the parentheses (or better yet absolute value bars) on the ln part
and... +C

Answer 9

Lol + C ... thanks

Answer 10

and you can drop the 1 because\[1+C_1=C_2\]