Question

Write the slope-intercept equation for the line that passes through (14, -2) and is perpendicular to 7x – 10y = 18

Answer 1

Slope intercept is y=mx + b
If you can first change your 7x - 10y = 18 equation to follow the format y=mx +b, you can find out your slope (m).
For a line to be perpendicular to another line, it must be the negative reciprocal..

Answer 2

7x - 10y = 18
-10y = -7x + 18
y = (7/10)x + 18
and thus the slope for the 7x - 10y = 18 equation is 7/10. To find the slope of the perpendicular equation you are looking for, you take the negative reciprocal = -10/7

Answer 3

That will equal m.
Then plug in the points and other info you know to the formula
y-y1=m(x-x1) and simplify.

Answer 4

y = mx + c
for perpendicular lines:
\[ m_1 m_2 = -1 \]
the given equation :
\[ y = 0.7x - 1.8 \]
The equation u want must be perpendicular to this
\[ \Rightarrow m = \frac{-1}{0.7} = -1.428 \]
\[ \Rightarrow y = c_2 - 1.428 x \]
But this satisfies y = -2 for x = 14
\[ -2 = c_2 - 20 \Rightarrow c_2 = -22 \Rightarrow y = -1.428 x -22 \Rightarrow 7y + 10x + 154 = 0 \]