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OpenStudy (anonymous):
Simplify
x 11th power
------------
a -2 power
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OpenStudy (lgbasallote):
this question is a little vague for me... is it \[\huge \frac{x^{11}}{a^{-2}}\]
OpenStudy (anonymous):
@lgbasallote Yes
OpenStudy (anonymous):
@lgbasallote oops! Its "a" not "x" for the top one
OpenStudy (lgbasallote):
ahh so \[\huge \frac{a^{11}}{a^{-2}}\]
OpenStudy (anonymous):
wait no! the bottom exponent is 7. That's the correct problem
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OpenStudy (lgbasallote):
...so \[\huge \frac{a^{11}}{a^{-7}}\]??
OpenStudy (anonymous):
no negative sign
OpenStudy (lgbasallote):
so \[\huge \frac{a^{11}}{a^7}\]
OpenStudy (anonymous):
yes
OpenStudy (lgbasallote):
are you familiar with the algebraic rule \[\huge \frac{x^m}{x^n} \implies x^{m-n}\]
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OpenStudy (anonymous):
Yes but for some reason i thought that the problem was division, not a fraction. I'm not really sure which one it is
OpenStudy (lgbasallote):
fraction is division
OpenStudy (anonymous):
Oh.
OpenStudy (lgbasallote):
so do you know how to solve \(\large \frac{a^{11}}{a^7}\) now?
OpenStudy (anonymous):
is it 2a to the 4th power? ---> 2a4
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OpenStudy (lgbasallote):
where did 2 come from?
OpenStudy (anonymous):
because there's 2 "a's"
OpenStudy (lgbasallote):
not exactly... like i said before \[\Large \frac{x^m}{x^n} \implies x^{m-n}\]
so \[\Large \frac{a^{11}}{a^7} \implies a^{11 - 7} \implies a^4\]
no 2
OpenStudy (anonymous):
Oh! ok! Thank you
OpenStudy (lgbasallote):
welcome
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