Simplify x 11th power ------------ a -2 power
this question is a little vague for me... is it \[\huge \frac{x^{11}}{a^{-2}}\]
@lgbasallote Yes
@lgbasallote oops! Its "a" not "x" for the top one
ahh so \[\huge \frac{a^{11}}{a^{-2}}\]
wait no! the bottom exponent is 7. That's the correct problem
...so \[\huge \frac{a^{11}}{a^{-7}}\]??
no negative sign
so \[\huge \frac{a^{11}}{a^7}\]
yes
are you familiar with the algebraic rule \[\huge \frac{x^m}{x^n} \implies x^{m-n}\]
Yes but for some reason i thought that the problem was division, not a fraction. I'm not really sure which one it is
fraction is division
Oh.
so do you know how to solve \(\large \frac{a^{11}}{a^7}\) now?
is it 2a to the 4th power? ---> 2a4
where did 2 come from?
because there's 2 "a's"
not exactly... like i said before \[\Large \frac{x^m}{x^n} \implies x^{m-n}\] so \[\Large \frac{a^{11}}{a^7} \implies a^{11 - 7} \implies a^4\] no 2
Oh! ok! Thank you
welcome
Join our real-time social learning platform and learn together with your friends!