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What is the domain and range of the equation shown below
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\[y=\sqrt{x ^{2}-4}\]
you cant take the square root of a negative number
but you can take the square root of zero
also remember no matter what you sub into x you will get a positive number
because it is squared
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So, domain is (x^2 -4) >=0
Solve that
how?
because the square root of something must be gretaer than or equal to 0
\[x \le-2\] and \[x \ge2\]
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Is that right?
Yep thats right
thats the domain
And is the range \[y \ge0\]
Yep
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U r very correct
ok thank you. i was just checking.
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