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write as a single fraction 1+(3)/x+2
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Is the question \[1+\frac{3}{x+2}\]?
yeah
\[1+\frac{3}{x+2}\]\[=\frac{x+2}{x+2}+\frac{3}{x+2}\]\[=\frac{(x+2)+3}{x+2}\]\[=...?\]
(x+5)/x+2. but cant that simplify into 5/2 thusly making it 2 (1)/2
?
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Nope, you cannot :|
You can't cancel the unknowns like that..
so itd just be (x+5)/x+2?
Yup!
sweet!!
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@Callisto, but isn't this correct?: \(\large \frac{x+5}{x+5}=\frac{\cancel x+5}{\cancel x+5}=\frac{5}{5}=1 \) ???? :)
Of course not. Shouldn't it be: \[\large \frac{x+5}{x+5}=\frac{\cancel {x+5}}{\cancel {x+5}}=1\]???
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