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Chemistry 18 Online
OpenStudy (anonymous):

molarity and molality !

OpenStudy (anonymous):

See there your question is given like: 2g of a Substance is added to water... Can you tell me what is solute here and what is the solvent here ??

OpenStudy (anonymous):

solvent is water and solute is that 2g substance .. correct ?

OpenStudy (anonymous):

Yes..

OpenStudy (anonymous):

For finding molarity you need number of moles solute.. How will you find number of moles of solute because it is given in 2 grams.. ??

OpenStudy (anonymous):

i dont know !

OpenStudy (anonymous):

For that there is a formula you will use that..

OpenStudy (anonymous):

ah .. that previous one ?

OpenStudy (anonymous):

derived from molarity .. ?

OpenStudy (anonymous):

\[Number \; Of \; Moles = \frac{Grams \; Present}{Molecular \; Mass \; Of \; that \; Substance}\]

OpenStudy (anonymous):

No no that one.. This one I have written above now..

OpenStudy (anonymous):

how many formulas are there in this chapter ?

OpenStudy (anonymous):

Now let us try to implement this formula on a question so that you can understand it properly. There are as many formulas as there are hairs on your head.. Ha ha ha..

OpenStudy (anonymous):

what if am bald ?? :P

OpenStudy (anonymous):

Wait for one second my mummy is calling me.. Have a look on that formula and try to memorize it and understand it as well..

OpenStudy (anonymous):

okay !

OpenStudy (anonymous):

Then there are as many formulas as there are hairs on my head And I don't like to be bald..

OpenStudy (anonymous):

am not bald either .. i were just kidding :)

OpenStudy (anonymous):

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