find the slope of line containing pairs of points (-6,-10) (-12,-11)
(y2-y1)/(x2-x1)
the slope of the line containing points(x1,y1)and(x2,y2) is m=(y2-y1)/(x2-x1)
Insert each point into the formula y = mx + b to get -10 =-6m + b -11 = -12m + b Isolate b in each equation and solve for m
so -10= -6m -11= -12m
-4.1
Isolate b in both equations to get: b = 6m - 10 b = 12m - 11 now set b = b to get: 6m - 10 = 12m - 11
Now finish solving for m
subtract 6m from both sides
Let me know what m equals when you're done.
6m+-1
6m=-1 sorry
Subtract 6m from both sides; add 11 to both sides to get 11 - 10 = 12m - 6m
-1/6
11 - 10 = 1 12m - 6m = 6m
You end up with 1 = 6m
then dividing both sides by 6 to get m = ?
so m= -1/6 right?
m = 1/6 I was trying help you realize you made a sign mistake.
Oh I see..don't know why I do that
so the slope is 1/6
If you had it right the first time, I would have told you it was correct.
Anyway, now you know an alternate way to find the slope. Just be careful with the signs.
Thanks a bunch
I use to be so good at this haven't done math in forever
best subject health science and history. Your the best.
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