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Mathematics 7 Online
OpenStudy (anonymous):

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OpenStudy (anonymous):

\[x ^{n+1}-(x+1)^{n}=2001\] in positive integers x,n.

OpenStudy (anonymous):

@Yahoo! @Australopithecus <-- Lucy?

OpenStudy (anonymous):

@unkabogable

OpenStudy (anonymous):

are u familiar with modular arithmetic ?

OpenStudy (anonymous):

I never did well on the AMC anyway...

OpenStudy (anonymous):

\[x^{n+1}-(x+1)^n+1=2002\]LHS is divisible by \(x\) so .. \(x\) must be a divisor of \(2002\)

OpenStudy (anonymous):

I got it

OpenStudy (anonymous):

taking mod \(3\) and mod \(x+1\) will be helpful... only solution is \(x=13\) and \(n=2\)

OpenStudy (anonymous):

yes

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