Question

(7/x) - (1/7) = (2/x)

Answer 1

I would multiply every term by x and see what you get

Answer 2

\[\frac 7x - \frac 17 = \frac 2x\]
you can start by adding \(\frac 17\) to both sides
\[\implies \frac 7x = \frac 2x + \frac 17\]
now subtract \(\frac 2x\) from both sides
\[\implies \frac 7x - \frac 2x = \frac 17\]
if you notice.. \(\frac 7x\) and \(\frac 2x\) have common denominators so i can just subtract the numerators then vopy the denominator
\[\implies \frac{7-2}{x} = \frac 17\]
combine like terms
\[\implies \frac 5x = \frac 17\]
now cross multiply
\[\implies 5 \times 7 = x\]
does that help?

Answer 3

jinks

Answer 4

lol i had a different method

Answer 5

Thanks igbasallote. I have a few more questions. Can you help me?

Answer 6

only if you understood what i wrote above

Answer 7

I do for sure. I just solved one just like that but I had to factor instead. I just need help with reviewing Algebra II Trig. I can't remember a thing

Answer 8

so what's your question?

Answer 9

Find an equation of the vertical line through the point (-7.7, 1.9). Can you give me the equation and then I could see if I can figure it out myself?

Answer 10

here's a hint: the equation of a vertical line is x = something

Answer 11

X = 0?

Answer 12

here's another hint...

the equation of the HORIZONTAL line that passes through (1,2) is y = 2

the equation of the VERTICAL line that passes through (1,2) is x = 1

Answer 13

So it's just x = -7.7?

Answer 14

yup. you learn fast

Answer 15

That was just a dumb question on my part. Summer made me forget everything. I have a few more questions and I promise I will stop bugging you

Answer 16

lol. sure ask away

Answer 17

Find an equation for the line with the given properties. Express the answer using the slope-intercept form of the equation of the line.
X-intercept = 3; y-intercept = -4
Please keep giving me hints so I learn sorta on my own

Answer 18

if the x-intercept is 3...do you know how it looks like in ordered pair form?

Answer 19

What do you mean? (3,-4)?

Answer 20

when you see something like x-intercept = 1 this means the point is (1,0)

when you see something like y-intercept = 2 this means the point is (0,2)

does that help?

Answer 21

Yea I understand that. But what does that have to do with finding the question? I don't have the slope or anything.

Answer 22

when you are given two points and you are asked to find the equation of the line, you just use this formula \[\Large y - y_1 = \frac{y_2 - y_1}{x_2 - x_1} (x-x_1)\]
are you familiar with those notations?

Answer 23

Yea ok I couldn't remember that equation. Lgive me a second to see if I can solvent and get it right

Answer 24

I can't remember. I have 4= (4/3) * 3

Answer 25

y and x stay...they are variables..you dont substitute anything to them

Answer 26

you just substitute x1, x2, y1 and y2

Answer 27

Y=4/3x?

Answer 28

that wasnt what i meant....

Answer 29

first tell me what is x1?

Answer 30

X1=3

Answer 31

right. and what is x2?

Answer 32

0?

Answer 33

yes. y1?

Answer 34

-4,0

Answer 35

nope..

Answer 36

if the y-intercept is -4 then the ordered pair is (0,-4)

y1 is 0 and y2 is -4

got it?

Answer 37

Yea that's what I meant. Sorry. So what is the slope?

Answer 38

remember i said the formula is \[y - y_1 = \frac{y_2 - y_1}{x_2 - x_1} (x-x_1)\]
so if you substitute those you'll get \[y - 0 = \frac{-4 - 0}{0 - 3} (x- 3)\]
got it?

Answer 39

So it's y = 4/3x + 4?

Answer 40

I mean -4

Answer 41

yep

Answer 42

Ok thanks. Next questionn I just want to check to see if I got it right.

Answer 43

sure

Answer 44

Find the intercepts of the graph of the equation.

1/6x + 1/3y = 1

My equation is y = -1/2x + 3Are the intercepts (0,3)?

Answer 45

wait... what's 1/6 x + 1/3 y = 1?

Answer 46

that's the original equation?

Answer 47

Yep

Answer 48

hmm this is probably the best time for me to teach you another equation...the intercept formula.. when you have something like \[\frac xa + \frac yb = 1\]
the intercepts are just (a,0) and (0,b)

got it?

Answer 49

So my fractions 1/6 and 1/3 are x and y?

Answer 50

no.. 1/6 x is x/6 => x/a

1/3 y is y/3 => y/b

Answer 51

Ok so intercepts are (6,0) and (0,3) it matches my equation I said earlier when you graph them.

Answer 52

yup that is right

Answer 53

actually you can also use the intercept formula on that problem you had earlier about the equation with x-intercept 3 and y-intercept -4

Answer 54

so are we done here @Brybro ?

Answer 55

Perpendicular to the line x - 7y = 7

That equation is simply y = 1/7x + 1 in simplistic form right? So the slope would be 7?

Answer 56

close... the perpendicular slope would be NEGATIVE reciprocal

Answer 57

Graph the circle

X^2 + (y-1)^2 = 36

I have no clue what to do here

Answer 58

first find the center and radius of that equation

Answer 59

How do you do that?

Answer 60

the equation of a circle is [(x-h)^2 + (y-k)^2 = r^2\]
(h,k) is the center and r is the radius

Answer 61

equation of a circle is \[(x-h)^2 + (y-k)^2 = r^2\]

Answer 62

So 1 is the center and 1 is the radius?

Answer 63

?

Answer 64

i said (h,k) is the center and r is the radius...

Answer 65

Oh. My bad. So center is (1,1) and radius is 6?