A very important tutorial on the VBODMAS rule
THE VBODMAS RULE
'VBODMAS' (Vinculum - Bracket - Of - Division - Multiplication - Addition - Subtraction) rule should be applied for solving problems involving one or more mathematical operations like multiplication, division, addition, subtraction etc. Such problems are solved in the order of vinculum, bracket, of, division, multiplication, addition and subtraction. Remember 'Of' in VBODMAS means multiplication.
also don't copy paste
it is considered as plagiarism .. mention the link also @vishweshshrimali5
The VBODMAS rule is used to solve the equations which are not so in use
I will @mathslover .
do that
This rule is really only useful in knowing what to do in the case of something like \[\frac{ 5x }{ 3 }=2\] so that you know to multiply 3 to both sides and then divide out the 5. I think you're taking this too far vish lol.
@vishweshshrimali5 http://www.bankexam.co.in/uploads/exam_features/1008091281335443Simplification.pdf
As @Kainui also said ..... about \(\div\) sign........ CORRECT....... in the older times it was used. but now it has gone....... but I think it is important to have some knowledge about old things...... also SO here I go
@Kainui I am not doing to prove you wrong....... I just want to increase the knowledge of everyone
The VBODMAS rule states that whenever more that algebric operations are involved then First one should solve Vinculum , then solve what is in brackets, then of operation, then division, multiplication , addition and at last subtraction
It would be better if we use some examples to understand it
I would use the material from here http://assets.openstudy.com/updates/attachments/50307886e4b0ac2883169dcf-vishweshshrimali5-1345355779516-1008091281335443simplification.pdf u can even try them yourself
1. 45 - 4 x 6 - 5 + 14 \(\div\) 7 = ?
So, according to VBODMAS rule we should solve division first
so 14\(\div\) 7 = 2
equation remains 45 - 4 x 6 - 5 + 2 now solve multiplication so 4x6 = 24
now what remains 45 - 24 - 5 + 2 now use addition 45 +2 = 47 so what remains 47 - 24 - 5 now solve we get answer = 18
now some users said that I didn't mention question correctly
So, lets understand the meaning of 21\(\div\)3(10-3)
and next some users will say please mention right link ... haha jk
thanks a lot for this tutorial
Please don't interrupt @mathslover u will get the time for that too
I have right to interrupt..
so, 21\(\div\) 3 (10-3) = \(\cfrac{21}{3}(10-3)\)
right
and u may ask why ? just because of the same rule VBODMAS
We had to solve bracket first
we would get 10 - 3 = 7
right
Now do we have to solve division first or multiplication obviously division first so
It's very inconsistent to use the form (x)(y) with ÷. You should use (x)(y) and x/y together or x*y and x÷y together. Mixing the too together causes confusion and wastes everyone's time.
\[\cfrac{21}{3}\]
very right @Kainui
that makes the whole diff.
@Kainui I know that......... but I never created those signs.......We should know their meaning when they stand for one of the algebric operation division
So now we all can solve question no. 3 also.......... Can we ?
I don't think most of the people would have troubles with these equations: 21÷ 3 * (10-3) or \[\frac{ 21 }{ 3 } (10-3)\]
@Kainui if a sadistic professor would like to fail his students by confusing them using this thing, then this is worth knowing isn't it?
the BODMAS rule has no significance after one reaches a certain maturity level..only the brackets matter then !
oh believe me @shubhamsrg it's more useful than you think. if it isn't useful for you then maybe you havent learned it enough?
\[\int\limits_{1}^{10}21÷ 3(10-3)dx\]
ahh,,can you show me any example which proves me wrong??
@shubhamsrg there's your example, solve the integral lol.
bracket first,,so its 21 / 3*7 how does it matter whether you multiply or divide first here!!
If you divide first you get 49, if you mulitply first you get 1.
\[3\div2\times4=?\]
thats where brackets come into play.. any expression like that will assume it to be 21 / (3*7) same thing as 2+2/2 ..some might say ans is 2,,some 3 ..
these ques are good for lower classes..after a certain time,,one can certainly argue that expression is insufficient due to lack of brackets..
Time to stick a fork in this topic, it's done.
what is \[3\div2\times4=?\]
you cant predict really,,altough we will have to assume it (3/2) *4 hmm..
leaves 6 ..
but i wont say 3/8 is wrong..
huh, ? but D comes before M in VBODMAS
is VBODMAS a rule ?
I don't want to comment anymore on this topic..........
oh @vishweshshrimali5 was right .... I was wrong there sorry @vishweshshrimali5 for arguing you.
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