Question

without multiplying show that 2*9 is greater than 1*10

Answer 1

@vishweshshrimali5

Answer 2

Show that 10>18 ok np

Answer 3

oops sorry wait

Answer 4

edited

Answer 5

sorry for the mistake

Answer 6

without multiplying...then add

Answer 7

9+ 9 > 10

Answer 8

haah good @lgbasallote

Answer 9

divide both sides by 2
1*9 and other side 1*5
now divide both sides by 1
9>5 hence proved

Answer 10

My logic was really messed up on this one honestly. I was thinking, well, anything multiplied by 1 is really just that number, so I'm only proving 2*9 is greater than 10. Then I thought, well, 9 is only 1 less than 10, and any number greater than 1 that's one less than another number who's a multiple has to be larger than that other number.

Answer 11

how about this fun ques:
which is greater ?
e^(pi) or pi^e ??

Answer 12

Is there a way of thinking about this without just directly using a calculator? I kind of approximated e=2 and pi=3 and then figured 8<9, so thought pi^e must be larger, but its not. That approximation isn't really right.

Answer 13

why you took e=2 when actually e=2.7something ..

Answer 14

Just because I could do that in my mind. As long as it kept e<pi I figured it'd be fine. I can easily do 2^3 and 3^2 in my head lol.

Answer 15

2^100 > 100^2

Answer 16

this is the logic

Answer 17

see this
\[\log e ^{\pi}= \pi \log e=\pi\]
\[\log \pi ^{e} = e \log \pi =e \log (22/7) = e ( \log 22 -\log 7)\]

Answer 18

though i know that:
\[\large{e^{i\pi}=-1}\]

Answer 19

but i want it without much use of calculator..

Answer 20

@theyatin

Answer 21

yes @shubhamsrg it is simple..

e = 2 (approx.)
pi = 3(approx.)

2^3 < 3^2

Answer 22

then do it as maths lover is doing :P

Answer 23

:D.. logicana

Answer 24

well your ans is wrong..