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OpenStudy (anonymous):

find exact values of cosx where -pi

OpenStudy (anonymous):

is that the complete question? is there anything more to the problem?

OpenStudy (anonymous):

cosx will be a number between -1 and 1 given those x values....

OpenStudy (anonymous):

sorry theres more thats exact values of cosx sqrt3/2

OpenStudy (anonymous):

again exact values of x where cosxsqrt3/2

OpenStudy (anonymous):

so the question is to solve the equation: \(\large cosx=\frac{\sqrt3}{2} \), where \(\large -\pi < x \le \pi \) ???

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

since cos x is positive, your angle will come from the first and fourth quadrants.... remembering the unit circle, what cosine of what angle will give you sqrt3/2 ?

OpenStudy (anonymous):

is it 60 degrees

OpenStudy (anonymous):

not quite... check out page 3 here.... http://tutorial.math.lamar.edu/pdf/Trig_Cheat_Sheet.pdf

OpenStudy (anonymous):

remember, cosine is your x coordinate.....

OpenStudy (anonymous):

is it 90 degress

OpenStudy (anonymous):

no.... try again.... it's in the first quadrant... which angle has sqrt3/2 as it's x coordinate?

OpenStudy (anonymous):

30 degrees

OpenStudy (anonymous):

yes.... 30 degrees but you really should answer according to what the question asked... so your angle is pi/6...

OpenStudy (anonymous):

now, look at the fourth quadrant.... there's another angle that has sqrt3/2 as its x coordinate... what angle is that?

OpenStudy (anonymous):

are there any other values that should be entered for this question

OpenStudy (anonymous):

yes, that what my question above is about...

OpenStudy (anonymous):

is it 11pi/6

OpenStudy (anonymous):

good!!!

OpenStudy (anonymous):

but that's not the answer they want....

OpenStudy (anonymous):

they want an answer between -pi and pi

OpenStudy (anonymous):

thanks im definitely a big fan,

OpenStudy (anonymous):

you need to come up with an angle between -pi and pi that is coterminal with 11pi/6... can you tell me what angle that is?

OpenStudy (anonymous):

i,m not sure of that

OpenStudy (anonymous):

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