find exact values of cosx where -pi
is that the complete question? is there anything more to the problem?
cosx will be a number between -1 and 1 given those x values....
sorry theres more thats exact values of cosx sqrt3/2
again exact values of x where cosxsqrt3/2
so the question is to solve the equation: \(\large cosx=\frac{\sqrt3}{2} \), where \(\large -\pi < x \le \pi \) ???
yes
since cos x is positive, your angle will come from the first and fourth quadrants.... remembering the unit circle, what cosine of what angle will give you sqrt3/2 ?
is it 60 degrees
not quite... check out page 3 here.... http://tutorial.math.lamar.edu/pdf/Trig_Cheat_Sheet.pdf
remember, cosine is your x coordinate.....
is it 90 degress
no.... try again.... it's in the first quadrant... which angle has sqrt3/2 as it's x coordinate?
30 degrees
yes.... 30 degrees but you really should answer according to what the question asked... so your angle is pi/6...
now, look at the fourth quadrant.... there's another angle that has sqrt3/2 as its x coordinate... what angle is that?
are there any other values that should be entered for this question
yes, that what my question above is about...
is it 11pi/6
good!!!
but that's not the answer they want....
they want an answer between -pi and pi
thanks im definitely a big fan,
you need to come up with an angle between -pi and pi that is coterminal with 11pi/6... can you tell me what angle that is?
i,m not sure of that
|dw:1345456272976:dw|
Join our real-time social learning platform and learn together with your friends!