Verify if \[x+-\frac{3}{2}(x+y-2)+\ln|x+y-2|=c\] is a solution to \[(x+y) dx + (3x+3y-4)dy = 0\]
Or you could start with the latter equation and see if it ends up with the former equation if it's too hard. I substituted y with \[t=a_1x+b_1y => y = \frac{t-a_1x}{b_1}\] and it follows that\[dy=\frac{dt-a_1dx}{b_1}\]
diff equation can be done by sub \(z=x+y\)
\[\frac{dy}{dx}=\frac{x+y}{4-3(x+y)}\]
Well I have to solve it in a specific way. It's a homogeneous differential equation where M(x,y) and N(x,y) are linear but not homogeneous. The equations in M(x,y) and N(x,y) actually represent equations of lines, which in this case are parallel.
sorry i was out so u want to make it homogeneous with mapping \((x,y)\) to \((X,Y)\) so that the diff equation will be homogeneous in tems of \(X\) and \(Y\)
u can show that the sub \(X=x-x_0\) and \(Y=y-y_0\) will change the nonhomogeneous diff equation\[\frac{dy}{dx}=\frac{ax+by+c}{ex+fy+g}\]to homogeneous diff equation\[\frac{dY}{dX}=\frac{aX+bY}{eX+fY}\]where \((x_0,y_0)\) is solution of system\[ax+by+c=0\]\[ex+fy+g=0\]
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