Question

proof on quadratic equation :)

Answer 1

consider the quadratic equation \[ax^2+bx+c=0 \space a \neq 0\] dividing both sides by 'a' we gt\[x^2+\frac{b}{a}x+\frac{c}{a}=0\]\[x^2+\frac{2b}{2a}x+\left( \frac{b}{2a} \right)^2-\left( \frac{b}{2a} \right)^2+\frac{c}{a}=0\]\[\left( x+\frac{b}{2a} \right)^2-\left( \frac{b}{2a} \right)^2+\frac{c}{a}=0\]\[\left( x+\frac{b}{2a} \right)^2=\left( \frac{b}{2a} \right)^2-\frac{c}{a}\]\[x+\frac{b}{2a}={\sqrt{b^2-4ac}\over4a^2}\]\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

Answer 2

Gud work @jiteshmeghwal9

Answer 3

thanx @vishweshshrimali5 :)

Answer 4

:D

Answer 5

@sasogeek @UnkleRhaukus @waterineyes have a look :)

Answer 6

Yeah Great work using Latex...

Answer 7

thanx @waterineyes :)

Answer 8

Proof of quadratic formula, i.e: one of the only times any sane person would use completing the square :P Congrats :)

Answer 9

thanx @Traxter :)

Answer 10

Also in my opinion this proof should be on the syllabus for final year of high school, so many students use it without realising what it means!

Answer 11

yup :)