Question

Calculate by hand the inverse of the matrix

A = see my next post for the matrix

A. Check whether your
answer is correct. Use the inverse to solve both of the following sets of equations:
x +z = 2
x + y +z = 3
2x + 3y+z = 5
y +z = 4
x + y +z = 5
3x + y+2z = 9
(Hint: rename the variables in the second system of equations.)

Answer 1

\[A=\left[\begin{matrix}1 & 0 & 1 \\ 1 & 1 & 1 \\ 2 & 3 & 1\end{matrix}\right]\]

Answer 2

wow sorry

x +z = 2
x + y +z = 3
2x + 3y+z = 5
there is suppose to be a gap here.
y +z = 4
x + y +z = 5
3x + y+2z = 9

Answer 3

cofactor; transpose, divide by det = inverse

Answer 4

if the det = 0, you can prolly see why a matrix would not be invertible then

Answer 5

yep know how to find the inverse...how do you do the second part

Answer 6

oh they mean find the inverse of the next 2 system of equations...not the previous inverse

Answer 7

not use the previous inverse

Answer 8

i mean

Answer 9

\[Ax=b\]
\[x=A^{-1}b\]

Answer 10

since youve found the inverse; they want you to define the vector for "x" i believe

Answer 11

Inverse matrix can be calculated here step by step: http://www.emathhelp.net/calculators/inverse-of-matrix-calculator?i=%5B%5B1%2C0%2C1%5D%2C%5B1%2C1%2C1%5D%2C%5B2%2C3%2C1%5D%5D