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Mathematics 17 Online
OpenStudy (anonymous):

Determine the pH of a solution with a hydronium ion concentration of 1.6 x 10^-4 ?

OpenStudy (anonymous):

PH is -ve log of H+ ions please write ur question more briefly what 1.6*10^-4

OpenStudy (anonymous):

that is the whole questions

OpenStudy (anonymous):

so h+ ion concentration is 1.6*10^-4 ph is 4.2

OpenStudy (anonymous):

how did you get that?

OpenStudy (anonymous):

i hope my ans is right

OpenStudy (anonymous):

can you show your steps pleae so i can see how it is done

OpenStudy (anonymous):

here it is how to do that do't look at 4.2 -log(1.6*10^-4)

OpenStudy (anonymous):

hmm ok thank you

OpenStudy (anonymous):

find that i don't have cal so 4.2 may be wrong

OpenStudy (anonymous):

how did you get 4.2?

OpenStudy (anonymous):

-log(1.6)+log(10^-4)=Ph

OpenStudy (anonymous):

i think 4.2 is wrong u do cal

OpenStudy (anonymous):

i got -4.2?

OpenStudy (anonymous):

-log(1.6) = -.20

OpenStudy (anonymous):

log(10^-4)= -4

OpenStudy (anonymous):

log(ab)=loga +logb log( 1.6 x 10^-4 )= log1.6 +log10^-4 PH=-log[H+] log of 10^-4 is =-4 ok log of 1.6 is =0.204 ok now add them = -3.976 fine but PH is - log multiply -3.976 by -1 ph=3.976

OpenStudy (anonymous):

-.20+(-4) =-4.2

OpenStudy (anonymous):

oh ok ic

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