Determine the pH of a solution with a hydronium ion concentration of 1.6 x 10^-4 ?
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OpenStudy (anonymous):
PH is -ve log of H+ ions please write ur question more briefly what 1.6*10^-4
OpenStudy (anonymous):
that is the whole questions
OpenStudy (anonymous):
so h+ ion concentration is 1.6*10^-4 ph is 4.2
OpenStudy (anonymous):
how did you get that?
OpenStudy (anonymous):
i hope my ans is right
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OpenStudy (anonymous):
can you show your steps pleae so i can see how it is done
OpenStudy (anonymous):
here it is how to do that do't look at 4.2
-log(1.6*10^-4)
OpenStudy (anonymous):
hmm ok thank you
OpenStudy (anonymous):
find that i don't have cal so 4.2 may be wrong
OpenStudy (anonymous):
how did you get 4.2?
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OpenStudy (anonymous):
-log(1.6)+log(10^-4)=Ph
OpenStudy (anonymous):
i think 4.2 is wrong u do cal
OpenStudy (anonymous):
i got -4.2?
OpenStudy (anonymous):
-log(1.6) = -.20
OpenStudy (anonymous):
log(10^-4)= -4
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OpenStudy (anonymous):
log(ab)=loga +logb
log( 1.6 x 10^-4 )= log1.6 +log10^-4
PH=-log[H+]
log of 10^-4 is =-4 ok
log of 1.6 is =0.204 ok
now add them = -3.976 fine
but PH is - log multiply -3.976 by -1
ph=3.976