Question

If g(x) = 3x + 5, what is g^–1(x)?

Answer 1

if u mean
\[ \large g^{-1}(x) \]
then just solve for \(x\) the equation
\[ \large y=g(x)=3x+5 \]

Answer 2

YES

Answer 3

solve the equation and tell what u got

Answer 4

X=-1 2/3

Answer 5

no

Answer 6

u have
\[ \large y=3x+5 \]
first substract 5 from both sides

Answer 7

x= -5+y/3

Answer 8

u r missing some parenthesis!!!!!!

Answer 9

where

Answer 10

g-1= ( g(x) - 5 )/3

Answer 11

do u see the difference between
\[ \large x=-5+\frac{y}{3} \]
(this is what u wrote) and
\[ \large x=\frac{-5+y}{3}=(-5+y)/3 \]

Answer 12

which one is correct??

Answer 13

the second one

Answer 14

yes!!
do u see how important parentheses are???
they can change completely an expression!!!!!

Answer 15

so
\[ \large g^{-1}(y)=\frac{y-5}{3} \]