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Mathematics 8 Online
OpenStudy (anonymous):

Which graph shows the solution for the inequality -7x-11<-109

OpenStudy (saifoo.khan):

Did you tried solving?

OpenStudy (anonymous):

here are the graphs

OpenStudy (anonymous):

yeah but it doesnt seem right

OpenStudy (saifoo.khan):

What did you got?

OpenStudy (anonymous):

-7

OpenStudy (saifoo.khan):

\[-7x-11<-109\] \[-7x < -109 + 11\] \[-7x < -98\]

OpenStudy (anonymous):

umm....i dont get it and did u look at the attachments??????????????

OpenStudy (anonymous):

Akeller, first solve the equation for x just as you would if the < sign was an = sign. Algebraic manipulation still works with inequalities.

OpenStudy (saifoo.khan):

Moving along: \[0 < -9x + 7x\]Flip action: \[7x - 98> 0\]\[7x > 98\]\[x > 14\]

OpenStudy (anonymous):

do wat @Traxter

OpenStudy (saifoo.khan):

And @Traxter is correct.

OpenStudy (saifoo.khan):

You have to calm down, solve the given inequality first, rather than rushing towards the attachments.

OpenStudy (anonymous):

Rearrange the equation and simplify with x on one side. A lot of students think that algebra with inequalities is different than usual algebra but it's exactly the same. The only thing you have to watch out for is that you change the inequality (> to < or vice versa) if you multiply or divide by a negative number.

OpenStudy (anonymous):

okay so wat do i do first

OpenStudy (anonymous):

So in the same way that if you were solving -7x-11=-109, you would start off by moving the constants to one side and dividing to get x on its own.

OpenStudy (anonymous):

so you would add 11 to both sides

OpenStudy (anonymous):

Yes that would be the first step. What's next?

OpenStudy (anonymous):

then you would divide -7 to the answer of -109+11 which is -98

OpenStudy (anonymous):

which is a +14

OpenStudy (anonymous):

Excellent :) now this is the only thing different with the algebra you're used to. When you divide (or multiply) by a negative number you have to flip the inequality. What do you end up with?

OpenStudy (anonymous):

x>14

OpenStudy (anonymous):

Well done :)

OpenStudy (anonymous):

so what graph would it be

OpenStudy (anonymous):

Do you know what sort of circle you use to represent a strict inequality on a number line (i.e. >, where you don't include the value at the circle)?

OpenStudy (anonymous):

yeah for <> open circle and the other ones closed circle i think it is the first graph

OpenStudy (anonymous):

You're right, and it is indeed the first graph.

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

No problem, well done for doing most of the work yourself :)

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