(These questions are the ones i got wrong on my test I need someone to help me answer them please.) What are the solutions of the system? Using a graphing calculator.
y=x^2+4.6x+4.7
y=3.3x-3.7

A. (-3.47,3.48) and (2.17, -15.17)
C. (-3.47, -15.17) and (2.17,3.48)
D. No solution

Question

(These questions are the ones i got wrong on my test I need someone to help me answer them please.) What are the solutions of the system? Using a graphing calculator. 
y=x^2+4.6x+4.7
y=3.3x-3.7

A. (-3.47,3.48) and (2.17, -15.17)
C. (-3.47, -15.17) and (2.17,3.48)
D. No solution

turingtest · Answer

you can use a graphing calculator?

anonymous · Answer

yes but i dont have one and the ones on the internet dont help

turingtest · Answer

if you have access to the internet you can use wolfram alpha: http://www.wolframalpha.com/ http://www.wolframalpha.com/input/?i=plot%20y%3Dx%5E2%2B4.6x%2B4.7%2C%20y%3D3.3x-3.7%20&t=crmtb01

anonymous · Answer

like i dont know how to put it in the calculator

turingtest · Answer

that depends on the calculator I suppose
I wouldn't know really how to use them, I use wolfram usually

notice all I did was put "plot" with the equations separated by a comma and you can see them drawn out
do they intersect?

anonymous · Answer

ok i got that part but how do i get the answer

turingtest · Answer

what does it mean graphically to solve the system?
-it means finding the intersection of the two graphs
no calculator is really required

x^2+4.6x+4.7=3.3x-3.7
x^2+1.3x+8.4=0

now find the discriminant of this quadratic; if it is negative that means the equation has two complex roots, so there are no real intersections...

turingtest · Answer

if there were real solutions to this equation you would plug in the answers you get for x into each equation and get a set of ordered pairs

anonymous · Answer

well I think it is no solution but im not really sure and thats what i was thinking bout the calculator it makes no since

turingtest · Answer

$$ax^2+bx+c=0\implies x={-b\pm\sqrt{b^2-4ac}\over2a}$$the discriminant is$$b^2-4ac$$when it is >0 there are two distinct real roots
when it =0 there is a double real root
when it is <0 it is two complex roots

turingtest · Answer

if you can graph it the image is enough to see that they do not intersect since the vertex of the quadratic does not go below the line

anonymous · Answer

so is the answer no solution

turingtest · Answer

right

anonymous · Answer

ok thank you so much you really helped me

turingtest · Answer

no problem :)

anonymous · Answer

maybe you can help witht he next one im about to post

anonymous · Answer

*the

turingtest · Answer

maybe, but I'm doing a few things at once
please post separately each problem, many others can help you I promise