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\[(x + \frac{1}{x})^2 - \frac{3}{2}(x - \frac{1}{x}) = 4\]
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expand it first multiply both sides by a multiple of x to get rid of the denominator move everything to one side then attempt to factor
Finally you will get : \[(x - \frac{1}{x})^2 - \frac{3}{2}(x - \frac{1}{x}) = 0\]
\[x - \frac{1}{x} = 0 \implies x^2 = 1\]
Or : \[x - \frac{1}{x} = \frac{3}{2}\]
@waterineyes whered the 4 go?
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\[(x + \frac{1}{x})^2 - 4 = (x - \frac{1}{x})^2\]
oh wait is a simple substitution \[u=x+\frac{1}{x}\] from there its a quadratic equation solve for u then solve for x
Then what will you put for x - 1/x ??
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