Question

What is the simplified form of.... (I have a picture to show the example)

Answer 1

you'll want to put the numerator in a single denominator (by LCD)..same with denominator...first

Answer 2

wait what?

Answer 3

1/xy? like that?

Answer 4

well not exactly... let me give a demonstration.. \[\frac ax + \frac by\]
first multiply the denominators

this gives you xy <--this becomes the denominator

then multiply the denominator of the second fraction to the numerator ofthe first fraction <--that gives you ay

then multiply the denominator of the first fraction to the numerator of the second fraction <--that gives you bx

so \[\frac ax + \frac by \implies \frac{ay + bx}{xy}\]
does that make sense?

Answer 5

sorta. so then it becomes x+y/xy?

Answer 6

yup

Answer 7

what about the denominator \[\frac 1y - \frac 1x\]

Answer 8

y-x/yx?

Answer 9

or wouldnt it be xy on the denominator because x goes first? Since its before in alphabetical order?

Answer 10

xy and yx are the same

Answer 11

commutative property ofmultiplication

Answer 12

ohh got it! so how do i finish this? my answer choices are this..

Answer 13

so... the expression becomes \[\Large \frac{\frac{x+y}{xy}}{\frac{y-x}{xy}}\]
do you see anything that can be cancelled?

Answer 14

umm yeah the denominators?

Answer 15

So its x+y/y-x?

Answer 16

yup

Answer 17

wait thats not an answer choice :/

Answer 18

y+x/y-x
y-x/y+x
x-y/x+y
x+y/x-y

Answer 19

lol wait.. i saw your mistake...

Answer 20

haha okay

Answer 21

\[\frac 1y - \frac 1x\]this should be \[\frac{x - y}{yx}\]

Answer 22

so the fraction would be \[\Large \implies \frac{\frac{x+y}{xy}}{\frac{x-y}{xy}}\]

Answer 23

ohh! I reversed them!

Answer 24

x+y/x-y?

Answer 25

yes

Answer 26

thankyou so much!

Answer 27

welcome