Question

The world's highest fountain of water is located, appropriately enough, in Fountain Hills, Arizona. The fountain rises to a height of 560 ft. (a) What is the initial speed of the water? (b) How long does it take for the water to reach the top of the fountain?

Answer 1

height (h) = 560ft
acceleration due to gravity (g) = 32 ft/s^2

To find the initial velocity start with the kinematic equation:
\[V_f^2-V_i^2=2ad\]Rearrange it (g=a and h=d) to get:\[\Delta V=\sqrt{2gh}\]Plug in known values:\[\Delta V=\sqrt{2(32ft/s^2)(560ft)}=189.3ft/s\]To find the time it takes to get to the top:\[t=\frac{\Delta V}{g}=\frac{189.3ft/s}{32ft/s^2}=5.9s\]

Answer 2

Thank you.

Answer 3

yw