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euler's formula
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use \[\Large e^{-\theta i}=\cos(\theta)-isin(\theta)\]
can you take me step by step?
use the above formula just replace \[\theta \] with \[\Large \frac{\pi}{6}\] and you will get answer.
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what about e^-1?
\[e^{-1}=e^{ii}\]? just thinking out loud...
e^(-1-pi/6)= e^-1 * e^-(pi/6) ?
e^-1[cos(pi/6) - sin(pi/6)]
\[\sqrt{3}\]/2*e -i 1/2*e
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yes it is correct at the end it should also be -1/2e^-1 (you missed -1 in the exponent.
thank you for your help
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