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Mathematics 13 Online
OpenStudy (anonymous):

euler's formula

OpenStudy (anonymous):

OpenStudy (anonymous):

http://en.wikipedia.org/wiki/Euler's_formula

OpenStudy (anonymous):

use \[\Large e^{-\theta i}=\cos(\theta)-isin(\theta)\]

OpenStudy (anonymous):

can you take me step by step?

OpenStudy (anonymous):

use the above formula just replace \[\theta \] with \[\Large \frac{\pi}{6}\] and you will get answer.

OpenStudy (anonymous):

what about e^-1?

OpenStudy (turingtest):

\[e^{-1}=e^{ii}\]? just thinking out loud...

OpenStudy (anonymous):

e^(-1-pi/6)= e^-1 * e^-(pi/6) ?

OpenStudy (anonymous):

e^-1[cos(pi/6) - sin(pi/6)]

OpenStudy (anonymous):

\[\sqrt{3}\]/2*e -i 1/2*e

OpenStudy (anonymous):

yes it is correct at the end it should also be -1/2e^-1 (you missed -1 in the exponent.

OpenStudy (anonymous):

thank you for your help

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