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for t>=0, find when tlnt-t>0
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u want to \[t \ln t-t >0\]factor out \(t\) u have\[t(\ln t-1)>0\]now note that \(t>0\) so u just need to find \(t\) such that \(\ln t-1>0\)
Following on from the explanation by @mukushla: \[\ln t >1\] Consider what happens when ln t = 1. In this case t equals the exponential number e. Therefore the required condition (t * ln t) - t >0 is met when t > e
@omgitsana I hope you now understand the solution.
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