Question

sinx/1+cosx = cscx-cotx prove ls=rs

Answer 1

can you help me with something? can you give me a little more detail about the probelm/

Answer 2

I always hated this kind of useless question.

Answer 3

same here.. I mean it is not easy but if you know your stuff you solve it.

Answer 4

I'm afraid I don't. I was thinking it looked like you could turn it into sinx+tanx but really I'd rather do a trig substitution integral any day, good luck! =P

Answer 5

well how about we work backwards to get to the answer

Answer 6

\[sinx \div 1+cosx = cscx - cotx\]

Answer 7

let us start with cscx-cotx tell me what that is?

Answer 8

I don't think this question is right . . .

Answer 9

question is correct.

Answer 10

http://www.wolframalpha.com/input/?i=sinx%2F%281%2Bcosx%29+%3D+cscx-cotx

Answer 11

to do this problem use reciprocal functions

Answer 12

write the right side as
\[\Large \frac{1}{\sin(x)}-\frac{\cos(x)}{\sin(x)}\]
now take LCM sin(x)
\[\Large \frac{1-\cos(x)}{\sin(x)}\]
now multiply and divide the above with 1+cos(x) you will get the left side.

Answer 13

hey same 21 just wondering you could do that backwards as well and get to the same answer?

Answer 14

I think i'd lile to see that as well.

Answer 15

wait how do you get cosx/sinx from cotx?

Answer 16

@godorovg you mean to go from left side to prove right side ??

Answer 17

yes that is what I mean

Answer 18

always.
\[\Large \cot(x)=\frac{\cos(x)}{\sin(x)}\]
since
\[\Large \tan(x)=\frac{\sin(x)}{\cos(x)}\]
and
\[\Large \cot(x)=\frac{1}{\tan(x)}\]

Answer 19

oh okayy

Answer 20

see it works both ways sami-21 or I am wrong?

Answer 21

it works both ways.

Answer 22

sami- 21 i find it easier to work backwards with these problems it seems easier too me. you?

Answer 23

i find it easier the other way. in backwards approach you will have to do more steps.

Answer 24

sami -21 I know in some cases backwards won't work.