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How do I calculate the cube roots of 8 in the formula a+bj
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8 = 2*2*2
a + ib ------ 2 + 0i
use the following formula with n=3 and r=8 use k=0,1,2 \[\Large =r^{\frac{1}{n}}[\cos(\frac{\theta}{n}+\frac{2 \pi k}{n}+isin(\frac{\theta}{n}+\frac{2 \pi k}{n}]\] where \[\theta =0\]
what ^
Thanks
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@bmtana ,did u get it or still have doubts....we can help u better if u post the entire question....
Here is the question.....get the cube roots of 8 using the formula a+bj and give the main root is exponential form.
2^3 is the exponential form, and i believe yahoo had it right with his 2 + 0i for the formula a+bi
Thanks, that helped me a lot.
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