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Mathematics 13 Online
OpenStudy (anonymous):

..

OpenStudy (anonymous):

you can write the F1 as F1=yx'(w+w') am i right ?

OpenStudy (anonymous):

It looks right. .. Which rule did you apply and what about F2?

OpenStudy (anonymous):

i simply took common yx' for F2 use De Morgan's Law

OpenStudy (anonymous):

F2 = (y' + xw)' F2=(y')'.(xw)' F2=y(x'+w')

OpenStudy (anonymous):

Now, yx'(w+w') + y(x'+w')?

OpenStudy (anonymous):

you can simplify the F1 because w+w'=1 F1=yx'(w+w')=yx'(1)=yx' F1=yx'

OpenStudy (rsadhvika):

w+w' = 1

OpenStudy (anonymous):

F2?

OpenStudy (rsadhvika):

F2 cannot be simplified further. now we can take the sum expression F1 + F2 = yx' + y(x'+w')

OpenStudy (anonymous):

Thank you VERY much guys. I appreciate your assistance! Is any one of you having insight on Karnaugh Maps?

OpenStudy (rsadhvika):

yes

OpenStudy (rsadhvika):

btw, you see the sum expression can be simlified...

OpenStudy (anonymous):

Okay, I see.. .

OpenStudy (anonymous):

What's the final simplyfication please? F1+F2= y.w'?

OpenStudy (anonymous):

Final simplification : F1 + F2 = yx' + yx' + yw = yx' + yw

OpenStudy (anonymous):

Thanks! I confused myself and figured it out later on. Just in time for submition.

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