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you can write the F1 as F1=yx'(w+w') am i right ?
It looks right. .. Which rule did you apply and what about F2?
i simply took common yx' for F2 use De Morgan's Law
F2 = (y' + xw)' F2=(y')'.(xw)' F2=y(x'+w')
Now, yx'(w+w') + y(x'+w')?
you can simplify the F1 because w+w'=1 F1=yx'(w+w')=yx'(1)=yx' F1=yx'
w+w' = 1
F2?
F2 cannot be simplified further. now we can take the sum expression F1 + F2 = yx' + y(x'+w')
Thank you VERY much guys. I appreciate your assistance! Is any one of you having insight on Karnaugh Maps?
yes
btw, you see the sum expression can be simlified...
Okay, I see.. .
What's the final simplyfication please? F1+F2= y.w'?
Final simplification : F1 + F2 = yx' + yx' + yw = yx' + yw
Thanks! I confused myself and figured it out later on. Just in time for submition.
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