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OpenStudy (chmvijay):
right hand equation should contain chlorine please see that
OpenStudy (chmvijay):
recheck the equation
OpenStudy (moongazer):
Cr(+3)Br3(-1) + Na(+1)O(-2)H(+1) + Cl2(0) ----> Na(+1)Cr(+7)O4(-2) + Na(+1)Br(+1)O(-2) + Na(+1)Cl(-1) + H2(+1)O(-2)
The oxidation number is enclosed by parenthesis.
OpenStudy (moongazer):
is it correct?
OpenStudy (chmvijay):
yaaa correct
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OpenStudy (moongazer):
I think I got something wrong. Because when I identified which elements changed an oxidation number I saw more than 2.
OpenStudy (moongazer):
elements
OpenStudy (chmvijay):
let me know them
OpenStudy (moongazer):
Cr, Br, Cl
OpenStudy (chmvijay):
yaaa you are right
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OpenStudy (chmvijay):
equation is right naaa
OpenStudy (moongazer):
Is it possible to have 2 reduction and 1 oxidation in an reaction ? or 1 reduction and 2
oxidation
OpenStudy (chmvijay):
Cr(+3) -Cr(+7)
Cl2(0) -Cl(-)
Br(-) - Br(+1)
OpenStudy (chmvijay):
yaaa it is possible provided the electrons are balanced properly
OpenStudy (chmvijay):
after all what is it redox reaction
instead of one reducing agent if you use simaltaneously 2 reducing agent then definately both will reduce and themseleves get oxidised
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