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Chemistry 18 Online
OpenStudy (moongazer):

CrBr3 + NaOH + Cl2 ----> NaCrO4 + NaBrO + NaCl + H2O balance by redox

OpenStudy (chmvijay):

right hand equation should contain chlorine please see that

OpenStudy (chmvijay):

recheck the equation

OpenStudy (moongazer):

Cr(+3)Br3(-1) + Na(+1)O(-2)H(+1) + Cl2(0) ----> Na(+1)Cr(+7)O4(-2) + Na(+1)Br(+1)O(-2) + Na(+1)Cl(-1) + H2(+1)O(-2) The oxidation number is enclosed by parenthesis.

OpenStudy (moongazer):

is it correct?

OpenStudy (chmvijay):

yaaa correct

OpenStudy (moongazer):

I think I got something wrong. Because when I identified which elements changed an oxidation number I saw more than 2.

OpenStudy (moongazer):

elements

OpenStudy (chmvijay):

let me know them

OpenStudy (moongazer):

Cr, Br, Cl

OpenStudy (chmvijay):

yaaa you are right

OpenStudy (chmvijay):

equation is right naaa

OpenStudy (moongazer):

Is it possible to have 2 reduction and 1 oxidation in an reaction ? or 1 reduction and 2 oxidation

OpenStudy (chmvijay):

Cr(+3) -Cr(+7) Cl2(0) -Cl(-) Br(-) - Br(+1)

OpenStudy (chmvijay):

yaaa it is possible provided the electrons are balanced properly

OpenStudy (chmvijay):

after all what is it redox reaction instead of one reducing agent if you use simaltaneously 2 reducing agent then definately both will reduce and themseleves get oxidised

OpenStudy (moongazer):

ok thanks, BRB

OpenStudy (moongazer):

I'll just eat and try to answer this . :)

OpenStudy (chmvijay):

yaaa good this must be the spirit

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