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MIT 18.01 Single Variable Calculus (OCW)
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how to prove that:
let x,y be two real no., for some rational no.z
x
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you should use two theorems,"Archimedes properties"and"minimum natural number theorem " let's show them. suppose x<y, by"Archimedes properties",we know "exist a integer n ,make n(y-x)>1" and them by "minimum natural number theorem" ,we know any elements of set of integer,either greater than nx or smaller than nx,when nx is not a integer.so,we get a minimum number "m>nx",make "(m-1)<nx<m". and,if nx is a integer,then (m-1)<=nx<m. so nx<=m<nx+1<ny. nx<=m<ny,x<=m/n<y. m,n are belong to integer. by the way ,my english is very poor.
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