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OpenStudy (anonymous):
\[\frac{ x ^{2}-4x+4 }{ x ^{2}+10+25 } * \frac{ x+5 }{ x ^{2}+3x-10}\]
OpenStudy (anonymous):
First factor all the terms
OpenStudy (anonymous):
im not good at factoring
OpenStudy (anonymous):
I think its x^2+10x+25
OpenStudy (anonymous):
x^2 +10+25 wouldnt it be (x+5)(x+5)?
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OpenStudy (anonymous):
Nope, Is that the correct question
OpenStudy (anonymous):
yes it is
OpenStudy (anonymous):
x^2-4x+4 = (x-2)(x-2)
OpenStudy (anonymous):
right?
OpenStudy (anonymous):
okay & for x^2 + 3x -10?
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OpenStudy (anonymous):
what do u think
OpenStudy (anonymous):
I think u must try it first
OpenStudy (anonymous):
\[((x-2)(x-2))/(x+5)(x+5) * (x+5)/(x+5)(x-2)\]
OpenStudy (anonymous):
thats the factorizing done. the rest you can cancel out common factors. and theres ur answer
OpenStudy (anonymous):
???
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OpenStudy (anonymous):
why the question marks?
OpenStudy (anonymous):
thank you @AidanNims
OpenStudy (anonymous):
enjoy and gald to help
OpenStudy (anonymous):
BUT HOW, x^2+10+25 = (x+5)(x+5)
OpenStudy (anonymous):
@AidanNims
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OpenStudy (anonymous):
lets look at it this way.(x+5)(x+5) operation is foil, ( first, outer,inner last) xtimes x =x^2 right?, x times 5 = 5x and then u do that again so u add 5x+5x=10x, then 5times 5 =25. thus u collect them all and thats x^2+10x +25 which is what we originally had