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Mathematics 4 Online
OpenStudy (anonymous):

Simplify completely

OpenStudy (anonymous):

\[\frac{ x ^{2}-4x+4 }{ x ^{2}+10+25 } * \frac{ x+5 }{ x ^{2}+3x-10}\]

OpenStudy (anonymous):

First factor all the terms

OpenStudy (anonymous):

im not good at factoring

OpenStudy (anonymous):

I think its x^2+10x+25

OpenStudy (anonymous):

x^2 +10+25 wouldnt it be (x+5)(x+5)?

OpenStudy (anonymous):

Nope, Is that the correct question

OpenStudy (anonymous):

yes it is

OpenStudy (anonymous):

x^2-4x+4 = (x-2)(x-2)

OpenStudy (anonymous):

right?

OpenStudy (anonymous):

okay & for x^2 + 3x -10?

OpenStudy (anonymous):

what do u think

OpenStudy (anonymous):

I think u must try it first

OpenStudy (anonymous):

\[((x-2)(x-2))/(x+5)(x+5) * (x+5)/(x+5)(x-2)\]

OpenStudy (anonymous):

thats the factorizing done. the rest you can cancel out common factors. and theres ur answer

OpenStudy (anonymous):

???

OpenStudy (anonymous):

why the question marks?

OpenStudy (anonymous):

thank you @AidanNims

OpenStudy (anonymous):

enjoy and gald to help

OpenStudy (anonymous):

BUT HOW, x^2+10+25 = (x+5)(x+5)

OpenStudy (anonymous):

@AidanNims

OpenStudy (anonymous):

lets look at it this way.(x+5)(x+5) operation is foil, ( first, outer,inner last) xtimes x =x^2 right?, x times 5 = 5x and then u do that again so u add 5x+5x=10x, then 5times 5 =25. thus u collect them all and thats x^2+10x +25 which is what we originally had

OpenStudy (anonymous):

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