Question

Simplify completely

Answer 1

\[\frac{ 5x ^{2}+9x-2 }{ x ^{2}+12x+20 } * \frac{ x ^{2}+17x+70 }{ 15x-3 }\]

Answer 2

can you factorize the respective numerators and denominators?

Answer 3

no, thats all i need help with & i can do the rest

Answer 4

look for example at 5x^2+9x-2
look for 2 numbers whose product is -2*5=-10 and whose sum is 9

Answer 5

((x+2)(5x-1))/(x+10)(x+2)* ((x+7)(x+10)/3(5x-1)

the way u apporach them is what numbers multiply to give lets say 70... well 7 and 10 . do they add to form the 17x yes cause 10 +7+17.

Answer 6

\[\frac{ (x+2)(5x+1) }{ (x+10)(x+2)} * \frac{ (x+10)(x+7) }{ 3(5x+1) }\]

(5x+1) cancels
(x + 10) cancels

\[\frac{ x+2 }{ x+2 } * \frac{ x+7 }{ 3} = 1 * \frac{ x + 7 }{ 3 } = \frac{ x+7 }{ 3 }\]

This, I cannot factor anymore.

Answer 7

thank you @AidanNims & @Compassionate

Answer 8

can you help me with one more @Compassionate ?

Answer 9

Yea.

Answer 10

great! .. hold on let me write it out

Answer 11

\[\frac{ x ^{2}+x-12 }{ x ^{2}-x-20 }\div \frac{ 3x ^{2}-24x+45 }{ 12x ^{2}-48x-60}\]

Answer 12

One sec, putting on music then I'll solve it. c:

Answer 13

okie dokie

Answer 14

Do you want me too factor it, or just give you the answer?

Answer 15

you can just give me the answer lol

Answer 16

Damn, this expression is walking all over me.

Answer 17

\[\frac{ (x+4)(x-3) }{ (x+4)(x-5) } - \frac{ 3(x-3)(x-5) }{ 4(3x^2-x-5) }\]

Answer 18

After this part I know what too do, I just can't figure out of to construct a common denominator.

Answer 19

okay thank you so much!