find the bases for this sets which are the subspaces for which alpha+beta is an element of w. a) w={(x;y;z)such that x=2z,y=-3z} b)w={(p;q;r)such that q=p+r}
a basis let's you define any vector in the subspace as a linear combination of the vectors in the basis. For (a), it looks like you can use z as the basis. x= 2z, and y= -3z (you could use x: z= (1/2)*x, y= (-3/2)*x , or y , for that matter)
ok then,
i'm i gonna assign it to zero then use matrices, according to the definition of bases?
I don't remembering doing this kind of problem, so I'm not much help in deciphering this question.
@mukushla check pls
@myininaya check this pls
remainder are you studying in university of limpopo? because we did the exact same thing a couple of days ago.
definetely but we did'n do this one
we only showed that it subspace we never prove as the bases
@UnkleRhaukus check this pls
yes m also trying to get some stuff online to prove it as a base.
\[W=\left\{ {\left.(x,y,z)\right| x=2z,\quad y=-3z}\right\} \]
\[(x,y,z)\quad\rightarrow\quad(2z,-3z,z)\]
then from here am i gonna let \[\alpha=(2z_1,-3z_1,z_1) ; \beta=(2z_2,-3z_2,z_2)\] ?
yeah
finding the linear combination let a,b be the element R then; |dw:1345620115837:dw| i'm not sure about this step
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