Find the interval of continuity and differentiability of the following function:

f(x) = (\sqrt (x^2 - x)) + (\frac (1 / ln(2x - 1)))

Step by step guide would be best

Question

Find the interval of continuity and differentiability of the following function:

f(x) = (\sqrt (x^2 - x)) + (\frac (1 / ln(2x - 1)))

Step by step guide would be best

anonymous · Answer

$$f(x)=\sqrt{x^2-x}+\frac{1}{\ln (2x-1)}$$

anonymous · Answer

yh thats the function

anonymous · Answer

under radical must be greater than or equal to zero so firstly we must have : 

$$x^2-x=x(x-1)\ge0$$

anonymous · Answer

and for the fraction?

anonymous · Answer

consider the ristrictions for input of  $\ln$  function : $$2x-1>0$$and dont forget to figure out when division by zero takes place$$\ln(2x-1)\neq0$$$$2x-1\neq1$$

anonymous · Answer

so what are you saying the interval of continuity is?

anonymous · Answer

i would say $$(1,\infty)$$

anonymous · Answer

and with regards to differentiability?