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Chemistry 14 Online
OpenStudy (anonymous):

High school Chemistry question?

OpenStudy (anonymous):

How many grams of a stock solution that is 85.5 percent H2SO4 by mass would be needed to make 150 grams of a 45.0 percent by mass solution? Show all of the work needed to solve this problem

OpenStudy (anonymous):

havn't worked with percent by mass solution in a while but this might help: conectration and volume can be calculated against each other with M1V1 = M2V2 with M = concentration(molarity) and V = volume. if we take the density of sulfuric acid = 1.83g/ml we get that 150 g = 45 ml = .045 L so that would give us (85.5)V1 = (45)(V2) V2 = 150/1.83 = 45ml/1000ml = .045 so doing the math has V1 = .043 L = 43 ml * 1.83g/ml = 78.69 g. hope that helps some and is right. like i said, it's been a while since i've looked at that stuff.

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