Question

Find the LCM of the set of polynomials:

Answer 1

\[41a^3c, 8b^4, b^2c^2\]

Answer 2

do you know LCM of 41 and 8?

Answer 3

note 41 is a prime number

Answer 4

So it would be 41*8 then, right?? which is 328

Answer 5

yes

Answer 6

how about the letters?

Answer 7

b^2 and b^4 ?

Answer 8

well a would still be a^3 because there's no other a...the b's would be b^4 in the final result? and c is c^2 as well

Answer 9

absolutely right

Answer 10

awesome sauce-om. thank you :)

Answer 11

lol - yw

Answer 12

one quick question though. is the LCM the number you get when you take the lowest number that multiplies into each number you're given? or is it the lowest number the numbers you're given multiply to be

Answer 13

its the lowest number into which the numbers you are considering divide into
if the numbers are large the best way to find the lcm is to write the numbers in prime factor form
eg

LCM of 156 and 180:

156 = 2*2 *3* 13
180 = 2*2*3*3*5

for each common factor take only one and use all the rest

so LCM is

2*2*3*3*5*13

Answer 14

hmmm okay. thanks again

Answer 15

yw