can a vector be squared ?
Yes, but it'll be the square of its magnitude
\[ v^2 = \vec v \cdot \vec v\]
You can square the individual components, or find its dot product with itself...but just "squaring a vector" doesn't have a whole lot of meaning.
say the vector is 1 by n
so that's a no?
only two vector product are defined ... dot and cross if you take dot product, you will square of magnitude if you take cross product you will end up zero.
how did you get zero for the cross product?
You can define what ever algebraic structure you please (group, ring, field) on vectors and define the operation(s) as long as they satisfy the structure axioms...but there is no common multiplication for vectors.
is multiplying by the duel vector like squaring the vector/?
Join our real-time social learning platform and learn together with your friends!