Question

What's the solution of the linear inequality

Answer 1

\[1+\frac{ 2 }{ x+1 }\le\frac{ 2 }{ x }\]

Answer 2

this inequality is not linear

Answer 3

well what's the possible solutions for x?

Answer 4

i don't know it is going to take a raft of algebra

Answer 5

\[1+\frac{ 2 }{ x+1 }\le\frac{ 2 }{ x }\]
\[1+\frac{ 2 }{ x+1 }-\frac{x}{2}\le 0\] is a start
now we have to add this stuff up

Answer 6

typo there, should be \[1+\frac{ 2 }{ x+1 }-\frac{2}{x}\le 0\]

Answer 7

\[\frac{x^2+x-2}{x(x+1)}\le 0\]

Answer 8

\[\frac{(x+2)(x-1)}{x(x+1)}\le 0\]

Answer 9

told you it as a pain
changes sign at \(-2,-1,0,1\) so you have to check on the intervals
\(x<-2\),
\(-2<x<-1\)
\(-1<x<0\)
\(0<x<1\)
\(x>1\)

Answer 10

there's no solution man

Answer 11

well, since it changes sign at each of these, you only have to check one

Answer 12

of course there is a solution

Answer 13

i got [-2, -1) U (0, 1]

Answer 14

wow can't believe it's a 11th grader math..

Answer 15

nvm, I wrote it incorrectly lol

Answer 16

yes, you are right. good work

Answer 17

why teachers give this as 11th grader math hwk, are they crazy?

Answer 18

and he said it has a 3min time limit -_________-

Answer 19

because it is an 11th grade question

Answer 20

but consider the difficulty... :S

Answer 21

thx Raphael!

Answer 22

nice work Raphael, but the [] and ()

Answer 23

and thx satellite!