how do i solve x^2 + 5x + 6 = 0

Question

anonymous · Answer

Is this how the question is phrased ?

unklerhaukus · Answer

$$x^2 + 5x + 6 = 0$$
$$x^2 + 2x+3x + 6 = 0$$
$$(x+3)(x+2)=0$$

anonymous · Answer

$$x^{2} + 5x + 6 = 0$$

anonymous · Answer

exactly what @UnkleRhaukus is doing. you factor it and then put both of them equal to 0

anonymous · Answer

so (x+3)=0 and (x+2)=0 and solve for x and you get....??

anonymous · Answer

i figure it out thank you

anonymous · Answer

np :)

anonymous · Answer

x2+5x+6=0

you're going to factor.

what you do is try to figure out what 2 numbers multiply to give you 6 but add to give you 5.

In this case you would have 3 & 2

x2+2x+3x+6=0

Group them together

(x2+2x)+(3x+6)=0

Factor out what ever is possible

here its the x in the first group & 3 in the second

x(x+2)+3(x+2)=0

from here you set both equations equal to 0 an solve for x

(x+2)=0  x=-2
(x+3)=0  x=-3

and that is your answer x=-2 & x=-3